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If you are looking for TeX support, please go to VietTUG.org
Problem #959
Cm=quy nap \(1+ \dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2^n1}<n\)
Status:  Closed  Start Date:  30122011  

Priority:  Normal  Due date:  
Assigned to:  tanphu  % Done: 
0% 

Category:  Quy nạp  
Target version:    
Votes:  0/0 
Description
Cm=quy nap: \(1+ \dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2^n1}<n\)
mọi người giúp em... mai em thi rồi!
History
Updated by tanphu about 1 year ago
 Subject changed from Cm=quy nap: 1+ \dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2^n1}<n to Cm=quy nap \(1+ \dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2^n1}<n\)
 Category set to Quy nạp
 Status changed from New to Assigned
 Assigned to set to tanphu
Updated by tanphu about 1 year ago
Em xem lại đề có trục trặc không? Thầy chưa thấy quy luật trong tổng ở vế trái.
Updated by tanphu about 1 year ago
 Status changed from Assigned to Closed