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Problem #806

giải pt

Added by tanthinh over 2 years ago. Updated over 2 years ago.

Status: New Start Date: 26-11-2010
Priority: Normal Due date:
Assigned to: - % Done:

0%

Category: -
Target version: -
Votes: 0/0

Description

a/ (3x/x^2-3x+1)+(7x/x^2+x+1)=-4
b/ (x^2+x-5/x)+4=(-3x/x^2+x-5)

History

Updated by tanphu over 2 years ago

    a)
    \(\dfrac{3x}{x^2-3x+1}+\dfrac{7x}{x^2+x+1}=-4\)
    \(\Leftrightarrow \dfrac{3}{x-3+\dfrac{1}{x}}+\dfrac{7}{x+1+\dfrac{1}{x}}\)
    Đặt \(t=x+\dfrac{1}{x}\) rồi giải tiếp

    b)

    \(\dfrac{x^2+x-5}{x}+4=\dfrac{-3x}{x^2+x-5}\)
    \(\Leftrightarrow x+1-\dfrac{5}{x}+4=\dfrac{-3}{x+1-\dfrac{5}{x}}\)
    Đặt \(t=x-\dfrac{5}{x}\) rồi giải tiếp.